Fixed typo in "center" calculation

7799d80a · paysan · a83263c6 · 7799d80a
Commit 7799d80a authored Apr 12, 2005 by paysan
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@@ -1073,7 +1073,7 @@ we add
 \begin{eqnarray}
 8 + 4 + 8 + 4 + 8 = 32\nonumber
 \end{eqnarray}
-(three widths and two avenues). $(80-31) / 2 = 24$.
+(three widths and two avenues). $(80-32) / 2 = 24$.

 \goodbreak
 So we could, crudely, define: